Question

solve the question..​

Answer 1

Hi,

Your answer is in the attachment ❤️

Answer 2

Answer:

Steps to construct the triangle

Draw a line segment BC=6 cm

At B, draw ∠CBE=60

o

Draw BF⊥BE

Draw the perpendicular bisector of BC intersecting BF at O.

With O as centre and radius equal to OB or OC draw a circle.

With D as centre and radius 5 cm, mark a point A on the circle.

Join AB and AC. This gives △ABC

With B as centre and radius 8 cm, mark an arc which intersect BC produced in C'.

Draw a line parallel to AC at C'.

Extend the line segment BA, which intersect the line passing through C' in A'.

Thus, △A

′

BC

′

is the required triangle.

Here, △A

′

BC

′

∼△ABC [AA similarity