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Given,
AB//CD
To find : X and Y
1)
Y + 35⁰ = 105⁰ (alternative Angles )
Y = 105⁰ - 35⁰
Y =70⁰
2)
105⁰ = 25⁰ + Z (angle in a straight line)
Z = 105⁰ - 25⁰
Z = 80⁰
3)
X + Y + Z = 180⁰ ( angle sum property )
X + 70⁰ + 80⁰ = 180⁰
X = 180⁰ - 150⁰
X = 30⁰
I took 3rd angle of that triangle as Z
Thank you
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