Question

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Answer 1

EXPLANATION.

⇒ a/b + b/a = 1.

As we know that,

Taking L.C.M in the equation, we get.

⇒ (a² + b²)/ab = 1.

⇒ a² + b² = ab.

As we know that,

Formula of :

⇒ (x³ + y³) = (x + y)(x² - xy + y²).

Using this formula in the equation, we get.

⇒ (a³ + b³) = (a + b)(a² - ab + b²).

⇒ (a³ + b³) = (a + b)(a² + b² - ab).

Put the value of (a² + b² = ab) in the equation, we get.

⇒ (a³ + b³) = (a + b)(ab - ab).

⇒ (a³ + b³) = (a + b)(0).

⇒ (a³ + b³) = 0.

Answer 2

Step-by-step explanation:

given :

• if a/b + a/b = 1, then, a + b = ?

to find :

• then, a + b = ?

solution :

first we can write formula :

• (x³ + y³) = (x + y)(x² - xy + y²)

then, we can l.C.M use :

• (a² + b²)/ab = 1

• a² + b² = ab

equation we we will write :

• a+ b equation we have = (a + b)(a² - ab + b²)

• a+ b equation we have = (a + b)(a² + b² - ab)

then, we will substitute them we get :

• a + b equation we have = (a + b)(ab - ab)

• a+ b equation we have = (a + b)(O)

• a+b equation we have = 0

learn more :

a + b formula :

a² – b² = (a-b)(a+b)

(a+b)² = a² + 2ab + b²

(a-b)² = a² – 2ab + b²

a² + b² = (a-b)² +2ab.

(a+b+c)² = a²+b²+c²+2ab+2ac+2bc.

(a-b-c)² = a²+b²+c²-2ab-2ac+2bc.

a³-b³ = (a-b) (a² + ab + b²)

a³+b³ = (a+b) (a² – ab + b²)