Question

Solve the question and proove lhs=rhs

Answer 1

LHS

convert all of them in sin and cos

so. (1+ cos theta/sin theta - 1/sin theta ). (1+sin theta/cos theta + 1/cos theta)

take LCM

{ (sin theta + cos theta -1) / sin theta } {( cos theta + sin theta +1) / cos theta }

Now we can see a identity of a^2 - b^2

{(sin theta + cos theta ) ^2. - 1 } sin theta cos theta

{(sin ^2 theta + cos ^2 theta +2 sin theta cos theta) -1}. sin theta cos theta

{(1 +2 sin theta cos theta) -1 } sin theta cos theta

(2 sin theta cos theta) / sin theta cos theta

2 = RHS

hence proved

I tried my best

Hope it helps