Question

solve the question answer​

Answer 1

Step-by-step explanation:

Question:-

A sum of ₹800 is in the form of 10-rupee notes and 20-rupee notes only. If the total number of notes is 50. Find the number of notes of each kind.

Solution:-

Let the number of 10 - rupee notes be x

And, the number of 20-rupee notes be y

Given, the total number of notes = 50

→ x + y = 50......(i)

● Sum of money = ₹800

→ 10x + 20y = 800

Dividing the whole equation by 10, we get

→ x + 2y = 80.....(ii)

Subtracting equation (i) from (ii)

→ x + 2y - (x + y) = 80 - 50

→ x + 2y - x - y = 30

→ x - x + 2y - y = 30

→ y = 30

Substituting y = 30 in equation (i)

→ x + y = 50

→ x + 30 = 50

→ x = 50 - 30 = 20

We have :-

• x = 20

• y = 30

Therefore:-

⇝ Number of 10 - rupee notes = 20

⇝ Number of 20 - rupee notes = 30