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Heya dear!!!!✌
✍Your answer⬇⬇
Since A(3,2) and B(-1,0) are the given vertices
And, let the other two vertices be C(x1,y1), D(x2,y2)
Since, we know that the diagonals of a parallelogram bisect each other
Hence, the point of intersection (2,-5) is the mid-point of the diagonal whose ends are (3,2) and (x1,y1)
Thus,
(3+x1)/2= 2 and (2+y1)/2= -5
=>x1= 1, y1= -12
Also, the point of intersection (2,-5) is the mid-point of the diagonal whose ends are (-1,0) and (x2,y2)
Thus,
(-1+x2)/2=2 and (0+y2)/2= -5
=>x2= 5, y2=-10
Thus, the other two vertices are (1,-12) and (5,-10)
Hope it helps❤
✍Your answer⬇⬇
Since A(3,2) and B(-1,0) are the given vertices
And, let the other two vertices be C(x1,y1), D(x2,y2)
Since, we know that the diagonals of a parallelogram bisect each other
Hence, the point of intersection (2,-5) is the mid-point of the diagonal whose ends are (3,2) and (x1,y1)
Thus,
(3+x1)/2= 2 and (2+y1)/2= -5
=>x1= 1, y1= -12
Also, the point of intersection (2,-5) is the mid-point of the diagonal whose ends are (-1,0) and (x2,y2)
Thus,
(-1+x2)/2=2 and (0+y2)/2= -5
=>x2= 5, y2=-10
Thus, the other two vertices are (1,-12) and (5,-10)
Hope it helps❤
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