solve the question attached
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let 1st no. be x
2nd no. be y
according to question
x+y=12
x=12-y
xy=27
put the value of x
12-y(y)=27
12y-y²=27
0= y²-12y+27
y²-9y-3y+27=0
y(y-9) -3(y-9)=0
(y-3)(y-9)=0
y-3=0
y=3
y-9=0
y=9
the two +ive numbers are 3,9
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thank you so much......
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