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For ∆ABC and ∆FED
Given :
AngleB = AngleE (90° each)
AngleA = AngleF
BC = ED
Since, for both the triangles, out of three, two angles given are equal, Therefore, by Angle sum property of ∆, third angles of both the ∆s angleC and angleD will be equal.
Now, For ∆ABC and ∆FED
angleB = angleE
BC = ED
angleC = angleD (proven above)
Hence ∆ABC is congruent to ∆FED by A.S.A congruency.
Hope This helps
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