Question

solve the question fast​

Answer 1

Answer:

1. y-2,y-3 ,2(.x-10) (x-12)( x-14)

Answer 2

hi mate

here is your answer

1.

${y}^{2} - 5y + 6$

${y}^{2} - 2y - 3y + 6$

$y(y - 2) - 3(y - 2)$

$(y - 2)(y - 3)$

so answer is 1st option.

2.

${x}^{3} - 23 {x}^{2} + 142x - 120$

$factors \: of \: - 120 \: are :$

$2 \times 2 \times 3 \times 2 \times 5 \times 1$

$- 2 \times - 2 \times - 2 \times - 3 \times - 5 \times - 1$

$let \: x = 1$

$so \: when \: putting \: x = 1$

$now \:divide \: {x}^{3}- 23{x}^{2} + 142x - 120$

$( {1}^{3} ) - 23( {1}^{2} ) + 142(1) - 120$

$1 - 23 + 142 - 120$

$142 - 142 = 0$

$it \: means \: x = 1 \: is \: a \: factor$

$so \: (x - 1) \: is \: a \: factor$

$now \: divide \: the \: equation \: by \:$

$(x - 1)$

(the solution of division is given in the picture)

$now \: here \: the \: factors \: are$

$({x}^{2} - 22x + 120)(x - 1)$

$( {x}^{2} - 12x - 10x + 120)(x - 1)$

$(x(x - 12) - 10(x - 12))(x - 1)$

$(x - 12)(x - 10)(x - 1)$

so the answer is 2nd option.

hope it helped❤✌

keep smiling❤