Question

Solve the question fast

Answer 1

Given 2(sin^6x + cos^6x) - 3(sin^4x + cos^4x)

2[(sin^2x)^3 + c(cos^2x)^3) - 3[(sin^2x)^2 + (cos^2x)^2]

We know that a^3 + b^3 = (a + b)^3 - 3ab(a + b), a^2 + b^2 = (a + b)^2 - 2ab

2[(sin^2 x + cos^2x)^3 - 3(sin^2x)(cos^2x)(sin^2 x + cos^2x))] - 3[(sin^2x + cos^2x)^2 - 2(sin^2x)(cos^2x))]


2(1)^3 - 3(sin^2x)(cos^2x)(1) - 3(1)^2  + 6(sin^2x)(cos^2x)


2 - 6sin^2xcos^2x - 3 + 6sin^2xcos^2x

2 - 3

= - 1.


Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks