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sorry i dont know
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f(x) =x^2-p(x+1) -c=x^2-px-(1+c)
a and b are zeros of the polynomial,
so, ab=(-1-c) and (a+b) = p
now, (a+1) (b+1)
=ab+a+b+1
=(-c-1) +p+1=(-c+p)
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