Math, asked by mjmukul, 2 months ago

solve the question fast .

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Answered by truptidenish5

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$\sin(42) \sin(48) - \cos(42) \cos(48) \\ = \sin(42) \cos(90 - 48) - \cos(42) \sin(90 - 48) \\ = \sin(42) \cos(42) - \cos(42) \sin(42) \\ = 0$

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