solve the question
Free 50 points
Attachments:
Answers
Answered by
15
Heya!!
---------------------------------
= 2^n(1-n) * 2^n(n-1) * 4^n / 2 * 2^n * 2^n-1
= 2^(n-n^2) * 2^(n^2-n) * 2^(2n) / 2 * 2^n * 2^n-1
= 2^(n-n^2 +n^2 - n+ 2n) / 2^(1+n+n-1)
= 2^(2n)/ 2^(2n)
= 1
Hope it helps uh!!
---------------------------------
= 2^n(1-n) * 2^n(n-1) * 4^n / 2 * 2^n * 2^n-1
= 2^(n-n^2) * 2^(n^2-n) * 2^(2n) / 2 * 2^n * 2^n-1
= 2^(n-n^2 +n^2 - n+ 2n) / 2^(1+n+n-1)
= 2^(2n)/ 2^(2n)
= 1
Hope it helps uh!!
Answered by
4
______________________
______________________
______________________
Similar questions