Math, asked by yneetu, 1 year ago

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Answered by Anonymous
15
Heya!!

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= 2^n(1-n) * 2^n(n-1) * 4^n / 2 * 2^n * 2^n-1

= 2^(n-n^2) * 2^(n^2-n) * 2^(2n) / 2 * 2^n * 2^n-1

= 2^(n-n^2 +n^2 - n+ 2n) / 2^(1+n+n-1)

= 2^(2n)/ 2^(2n)

= 1

Hope it helps uh!!
Answered by HolyGirl
4

{\huge{\blue\longrightarrow{\texttt{\orange A\red N\green S\pink W\blue E\purple R\red:}}}}

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1. \: p(8 - 2) = 12

\therefore p(6) = 12

\therefore p = 12 \div 6

 \green \Longrightarrow \blue{\fbox{p = 2}} \\  \\

 2. \: ( - 5)(z + 2) =  - 4

\therefore  - 5z - 10 =  - 4

\therefore - 5z =  - 4 + 10

\therefore - 5z = 6

\green \Longrightarrow \blue{ \boxed{ z =  - \frac{6}{5} }} \\  \\  \\

3. \: 6(k - 3) = 8

\therefore 6k - 18 = 8

\therefore 6k = 8 - 18

\therefore 6k =  - 10

\therefore k =  - \frac{10}{6}

\green \Longrightarrow \blue{ \boxed{ k =   - \frac{5}{3} }} \\  \\

______________________

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{\blue{\large{\overbrace{\underbrace{\dag  \: {\pink {\bigstar} \: {\green{Thanks \:Please }}\: {\pink{ \bigstar} \: \dag}}}}}}}

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