Question

solve the question from rd shrma class 10 ​

Answer 1

Let 1/3x+2y=u and 1/3x-2y=v. Then, the new system of equations is

2u+3v=17/5 ...(1)

5u+v=2 ...(2)

Multiplying eq.(2) by 3, we get

15u+3v=6 ...(3)

Subtracting eq.(1) from eq.(3),

15u+3v-2u-3v=6-17/5

⇒13u=13/5

⇒u=1/5

Putting u=1/5 in eq,(2),

5(1/5)+v=2

⇒1+v=2

⇒v=1

Thus, we have

u=1/5 and v=1

Substituting back the values of u and v,

1/3x+2y=1/5 and 1/3x-2y=1

⇒3x+2y=5 and 3x-2y=1

Solving these equations, we get

x=1 and y=1.