Question

solve the question given

Answer 1

$\LARGE\mathfrak{\pink{Solution:-}}$

$\large\mathbb{\orange{GIVEN:-}}$

• AX is the bisector of ∠BAC .
• P is any point on AX .

$\large\mathbb{\purple{TO \:PROVE:-}}$

• Perpendicular drawn from P to AB and AC are equal .

$\large\mathbb{\red{ACCORDING \:TO\: THE\: QUESTION:-}}$

In ∆ AMP and ∆ ANP :-

∠ 1 = ∠ 2 (As ∠BAC is the bisector of AX.)

∠ AMP = ∠ ANP = 90°(Given)

AP = AP (Common)

$\therefore$, ∆ AMP ≅ ∆ ANP (By Angle-Angle-Side Criteria)

So, MP = NP (By C.P.C.T)

$\Large{\mathfrak { \boxed{\green {Hence \: Proved}}}}$

Answer 2

Answer:

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Step-by-step explanation: