Solve the question given below
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let third angle be x
now,
Angle A + B + C = 180. ( sum of interior angle of triangle)
116 +x = 180
x = 180-116
x = 64°
the third angle is 64°
now the difference between is 24°
A + B =116°
A= 116-B
now,
A-B = 24°
(116 - B )- B =24°
116 -2B = 24°
-2B = 24 -116
-2B= -92
B = 92/2
B= 46
Now substitute the value of B in A =116-B
A= 116 -46
A = 70
Hence the angles be 70° , 46° , 64°
now,
Angle A + B + C = 180. ( sum of interior angle of triangle)
116 +x = 180
x = 180-116
x = 64°
the third angle is 64°
now the difference between is 24°
A + B =116°
A= 116-B
now,
A-B = 24°
(116 - B )- B =24°
116 -2B = 24°
-2B = 24 -116
-2B= -92
B = 92/2
B= 46
Now substitute the value of B in A =116-B
A= 116 -46
A = 70
Hence the angles be 70° , 46° , 64°
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