Question

solve the question given in the attatchment.

Answer 1

$hi \\ here \: is \: the \: solution \\ \\ let \: the \: smaller \: number \: be \: x \\ and \: the \: larger \: number \: be \: 2x \\ \\ so \\ we \: got \: an \: equation = 50 - 2x = 40 - x + 2 \\ \\ solution = = > \\ 50 - 2x = 40 - x + 2 \\ 50 - 40 - 2 = 2x - x \\ 10 - 2 = x \\ 8 = x$


so the numbers :--
(X) = 8
2x = 16

Answer 2

Answer:

8 and 16 are the numbers

Step-by-step explanation:

Let the small number be x .

Then the larger number is 2 x as it is twice the smaller number .

When the larger number is subtracted from 50 .

50 - 2 x

This is two more than twice number subtracted from 40 :

40 - x + 2

50 - 2 x = 40 - x + 2

= > - 2 x + x = 42 - 50

= > - x = - 8

= > x = 8

Hence the smaller number is 8.

The bigger number is twice .

Hence it is 8 × 2 = 16 .