Math, asked by disha9573, 3 months ago

solve the question home work !! ​

Attachments:

Answers

Answered by MRDEMANDING
1

Given :-

  • A scooter moving at a speed of 10m/s is stopped by applying brakes which produce acceleration of -0.5m/s².

To find :-

  • How much distance will be covered by the scooter?

Solution :-

  • Initial velocity = 10 m/s

  • Acceleration = - 0.5 m/s²

  • Final velocity = 0

According to third equation of motion

  • → v² = u² + 2as

  • Where " v " is final velocity, " u " is initial velocity, " a " is acceleration and " s " is distance.

  • → (0)² = (10)² + 2 × (-0.5) × s

  • → 0 = 100 - 1 × s

  • → 0 = 100 - s

  • → s = 100 m

Hence,

  • Distance will be covered by the Scooter is 100m

More to know :-

  • s = ut + ½ at² (second equation of motion)
  • v = u + at (first equation of motion)
  • Acceleration is the rate of change in velocity.
  • Acceleration in negative is known as retardation
Similar questions