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Given :-
- A scooter moving at a speed of 10m/s is stopped by applying brakes which produce acceleration of -0.5m/s².
To find :-
- How much distance will be covered by the scooter?
Solution :-
- Initial velocity = 10 m/s
- Acceleration = - 0.5 m/s²
- Final velocity = 0
According to third equation of motion
- → v² = u² + 2as
- Where " v " is final velocity, " u " is initial velocity, " a " is acceleration and " s " is distance.
- → (0)² = (10)² + 2 × (-0.5) × s
- → 0 = 100 - 1 × s
- → 0 = 100 - s
- → s = 100 m
Hence,
- Distance will be covered by the Scooter is 100m
More to know :-
- s = ut + ½ at² (second equation of motion)
- v = u + at (first equation of motion)
- Acceleration is the rate of change in velocity.
- Acceleration in negative is known as retardation
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