Question

Solve the question in attachment​

Answer 1

Answer:

HOPE THE ATTACHMENT HELPS YOU

Answer 2

Step-by-step explanation:

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$\text { This is Sweety Adihya }$❤️

cos(3/2π+x)cos(2π+x)[ cot(3/2π+x)+cot(2π+x)]

= sinx × cosx [ tanx+ cotx]

= sinx × cosx[ cos²x+sin²x÷ cosx.sinx]

=1

Hope it will help you

@ Sweety Adihya

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