Question

solve the question
in figure AO OB . find angle AOC and Angle BOC plz check the photo ​

Answer 1

Answer:

∠AOC=65° & ∠BOC=25°

Explanation:

AO⊥OB

So, ∠AOB=90°

∠AOB=∠AOC+∠BOC

As per question,

(2x-5)°+(x-10)°=90°

⇒2x-5+x-10=90

⇒3x-15=90

⇒3x=90+15

⇒3x=105

⇒x=105/3

⇒x=35

So, x=35

Therefore,

∠AOC=(2x-5)°=(2×35-5)°=65°

∠BOC=(x-10)°=(35-10)°=25°

∴∠AOC=65° & ∠BOC=25°.

Hope it helps you...

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Answer 2

Answer:

Required angles are 65° and 25°.

Step-by-step explanation:

Given angle AOC is 90°.

So, it clear that sum of (2x-5)° and (x-10)° is 90°.

According to question,

${(2x - 5)}^{o} + {(x - 10)}^{o} = {90}^{o} \\ {(2x - 5 + x - 10)}^{o} = {90}^{o} \\ {(3x - 15)}^{o} = {90}^{o} \\ 3x = {90}^{o} + {15}^{o} \\ 3x = {105}^{o} \\ x = \frac{ { {105}^{o} }}{3} \\ x = {35}^{o}$

So, required both angles are

${(2x - 5)}^{o} = {(2 \times 35 - 5)}^{o} = {65}^{o}$

and

${(x - 10)}^{o} = {(35 - 10)}^{o} = {25}^{o}$

Know more about right angle,

A right angle is an angle that measures 90 degrees. This is the corner that is most often encountered in our daily lives. It can be seen in the corners of the room, on the edges of the boxes, on the mobile phone screen, etc. The sides of a square and a rectangle always form a right angle with each other. In radians, this is expressed as /2. Let's talk more about right angles in this article.

A right angle is a 90° angle. If two rays intersect and form a 90-degree angle or are perpendicular to each other at the point of intersection, they are said to form a right angle.

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