Question

Solve the question in pic​

Answer 1

Step-by-step explanation:

Let the zeroes of p(x) be a and ß

p(x)= 3x²-0x+5

a+ß = -b/a

= 0/3 = 0

aß = c/a

= -5/3

Hence, the the relationship between zeroes of p(x) and its coefficients is verified.

a+ß = 0 --------(1) and aß = -5/3 i.e ß = -5/3a ---------(2)

a-5/3a = 0 ----------From (1) and (2)

3a²-5 = 0

–––––

3a

3a²-5 = 0

3a² = 5

a² = 5/3

a = √5/√3 -----------(3)

ß = -5 ÷ 3a ---------- From (2) and (3)

ß = -5 ÷ 3√5

-------

√3

ß = -5 *√3

-------

3√5

ß = -5 *√15

-------

15

ß = -√15

-------

3