Math, asked by rajasriv, 3 days ago

Solve the question in the above image

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Answers

Answered by mayankrawat49
1

Answer:

Use Heisenberg's uncertainty principle.

For example [Δx=

4πmΔv

h

]

Here, Δx is the uncertainty in the position.

Δv is the uncertainty in velocity

m is the mass of Particle.

Given,m=40g=0.04kg

Δv=2%ofv=2×

100

45

=0.9m/s

h=6.626×10

−34

J.s

Now,Δx=

(4×3.14×0.04×0.9)

6.626×10

−34

=1.4654×10

−33

m

Answered by shubhambhutesjs04635
0

Answer:

Step-by-step explanation:

= 6.6-4.125/5.5-4 2/5

= 2.475/1.1

= 2.25

______

= 2 2/35 + 1.44+1.25 / 1.5×3 5÷7

= 2.057 ÷ 2.69 / 5.571

= 0.764 / 5.571

______

= 2.25 - 0.764 - 9/13  /   5.571 - 5.6÷3 m 4/15

= 2.25 -0.764 - 0.692  /   5.571 - 5.6 ÷ 336

= 2.25 - 0.764 - 0.692  /  5.571 - 0.017

= 2.25 - 0.072 /  5.554 of 3.25 × 13 1/2

= 2.25 - 0.072 /  5.554 of 3.25 × 13.5

= 2.25 - 0.012 of 3.25 × 13.5

= 2.25 - 0.012 / 3.25 × 13.5

= 2.403 / 3.25 × 13.5

= 0.739 × 13.5

ans = 9.9765

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