Question

solve the question in the attachment ​

Answer 1

Answer:

Answer:

Given : p(x) = x² - 4√3x + 3p(x)=x²−4√3x+3

On comparing this with ax² + bx + c, we get

a = 1, b = - 4√3, c = 3

It is given that α and β are the zeroes of the above polynomial.

Now,

• Sum of zeroes =α + β = - b/aα+β=−b/a

→ α + β = - (- 4√3)/1α+β=−(−4√3)/1

→ α + β = 4√3α+β=4√3

• Product of zeroes =αβ = c/aαβ=c/a

→ αβ = 3/1αβ=3/1

→ αβ = 3αβ=3

To Find : α + β - αβα+β−αβ

Putting known values in it.

→ (4√3) - (3)(4√3)−(3)

→ 4√3 - 34√3−3

→√3(4 - √3)√3(4−√3) ✓✓

Answer 2

SOLUTION:-

Given: p)=x* -4/3x t 3ptx)=x*-4/3xt3

On comparing this with ax" t bx t c, we get

a =1, b=-4V3, C =3

It is given that a and B are the zeroes of the

above polynomial.

Now,

Sum of zeroes a tB=- b/aa+p=-b/a

*a+B=-(-4/3)y1a+B=1-4/3}1

atß =4/3a+B=4v3

Product of zeroes =aß = c/aaß=c/a

aß = 3/1aß-3/1