solve the question in the attachment
Answers
Answer:
Angle of refraction at A is 30°
Explanation:
Given,
A Ray of Light Falls on a Transparent Sphere with Centre C as Shown in the Figure. the Ray Emerges from the Sphere Parallel to the Line AB.
To find: Angle of refraction at A.
Solution:
According to Snell's laws of refraction, the sine of angle of incidence and the sine of angle or refraction is constant and that constant is called refractive index. (μ)
i.e sin(i) / sin(r) = μ
here, i = 60° , μ = √3
Substituting the values,
sin 60° / sin(r) = √3
or, sin(r) = sin 60° / √3
or, sin(r) = √3 / (2 *√3)
or, sin(r) = 1 / 2
or, r = sin⁻¹ ( 1/2)
or, r = 30°
Therefore, Angle of refraction at A is 30°
Given,
- A Ray of Light Falls on a Transparent Sphere with Centre C as Shown in the Figure. the Ray Emerges from the Sphere Parallel to the Line AB.
To find:
- Angle of refraction at A.
Solution:
According to Snell's laws of refraction, the sine of angle of incidence and the sine of angle or refraction is constant and that constant is called refractive index. (μ)
i.e sin(i) / sin(r) = μ
here, i = 60° , μ = √3
Substituting the values,
sin 60° / sin(r) = √3
or, sin(r) = sin 60° / √3
or, sin(r) = √3 / (2 *√3)
or, sin(r) = 1 / 2
or, r = sin⁻¹ ( 1/2)
or, r = 30°
- Therefore, Angle of refraction at A is 30°