Question

solve the question in the attachment​

Answer 1

HI,

here is the solution..
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$dimension \: of \: the \: table \: cover \: = 400cm \times 200cm \\ length \: of \: inner \: rectangle = = > 400 - 25 - 25 \\ = = > 350cm \\ bredth \: of \: inner \: rectngle = = > 200 - 25 - 25 \\ = = > 150cm \\ \\ area \: of \: table \: top = (length \times bredth) \\ = = > 350 \times 150 \\ = = > 52500 \: {cm}^{2} \\ \\ area \: of \: table \: top \: in \: meters \: \\ = = > \frac{52500 \: {cm}^{2} }{100 \times 100} \\ = = > 5.25 {m}^{2}$