Question

Solve the question in the attachment!

Request :

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Answer 1

Answer:

Step-by-step explanation:

Given: ΔAMP ≅ ΔAMQ

to prove: 1)PM = QM

               2) ∠PMA = ∠QMA

               3) AM = AM

               4) ΔAMP ≅ ΔAMQ

proof: 1)PM = QM

as ΔAMP ≅ ΔAMQ,

therefore, PM = QM                                          -1 (by CPCT)

2) ∠PMA = ∠QMA,

as ΔAMP ≅ ΔAMQ,

therefore , ∠PMA = ∠QMA                                -2 (by CPCT)

3) AM = AM

as in ΔAMP and ΔAMQ,

AM is common , so AM = AM                          -3 (by CPCT)

4) ΔAMP ≅ ΔAMQ

as already given in the question ,

therefore. ΔAMP ≅ ΔAMQ                              -4 (by CPCT)

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