Question

solve the question in the photo​

Answer 1

Answer:

see the image

hope it helps you out ☺️

Answer 2

By data

• Power of electric bulb , P = 100 watt

• Rated voltage, V = 220 volt.

Let's find the resistance of the electric bulb, R.

We know that,

$P = \dfrac{ {V}^{2} }{R} \\ \\ 100 = \dfrac{ {(220)}^{2} }{R} \\ \\ 100 \times R = 220 \times 220 \\ \\ R = \dfrac{220 \times 220}{100} \\ \\ R = \dfrac{22 \times 22 \times 100}{100} \\ \\ R = 22 \times 22 \\ \\ R =484 \: ohm$

The resistance of the electric bulb is 484 ohm.

Again by data,

• Operated voltage, V = 110 volt
• Resistance, R = 484 ohm.

Let the power consumed be P.

$P = \dfrac{ {V}^{2} }{R} \\ \\ = \dfrac{ {(110)}^{2} }{484} \\ \ = \dfrac{110 \times 110}{22 \times 22} \\ \\ = \dfrac{110}{22} \times \dfrac{110}{22} \\ \\ = \dfrac{10}{2} \times \dfrac{10}{2} \\ \\ = 5 \times 5 \\ \\ P= 25 \: watt$

The power consumed by the electric bulb when operated at 110 volt is 25 watt.

The power consumed by the electric bulb when operated at 110 volt is 25 watt.Option 1 is right.