Question

solve the question in the photo..​

Answer 1

$\huge \pink {Anneyong}$

SOLUTION :--

$\frac{0.216 + 0.064}{0.36 + 0.16 - 0.24} \\ \\ = \frac{ ({0.6}^{3}) + {0.4}^{3} }{ {(0.6)}^{2} + {(0.4)}^{2} - 0.6 \times 0.4 }$

Let 0.6 be a

And 0.4 be b..

$\frac{{a}^{3} + {b}^{3} }{ {a}^{2} + {b}^{2} - ab } = a + b \\ \\ = 0.6 + 0.4 \\ \\ = = > 1$

Answer 2

The answer is 1...............