Solve the question in the pic. Its urgent
No spams or u will be reported.
Attachments:
Answers
Answered by
1
Answer:
Area of trapezium = 1/2 ×h ×(sum of parallel sides(a+b)
Given : A = 50 m²
h = 5(√5-1)m
50 = 1/2 × 5(√5-1) × (x+x+10)
50×2 = 5(√5-1) × (2x+10)
100 = 5(√5-1) ×(2x+10)
20 = (√5-1) 2(x+5)
10 = (√5-1) × (x+5)
x+5 = 10/√5-1
x + 5 = 10(√5+1)/(√5)²-1
x+5 = 10(√5+1)/4
x+5 = 5(√5+1)/2
x = 5(√5+1)/2-5
x = 5√5+5-10/2
x = 5√5-5/2
x = 5(√5-1)/2
Similar questions