Question

solve the question jo shi answer dega brainless Mark krunga​

Answer 1

Step-by-step explanation:

Given:

⇒ABCD is a rhombus

⇒For ΔBCD

Perimeter

=8+30+30

=108 cm

⇒2S=108 cm, S=54 cm

⇒Area of ΔBCD

A= √s(s−a)(s−b)(s−c)

=√ 54(54−48)(54−30)(54−30)

= √54×6×24×24

= 72×6

=432m²

⇒Area of field

=2× Area of ΔBCD

=2×432 m²

=864 m²

⇒Area of grass field each cow be getting

=864/18 =48 m²