solve the question no. 19
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x is ethanol
y is ethene
z is ethane
y is ethene
z is ethane
AnujRawat1:
pls proper answer
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x=ethanol CH3-CH2OH
y=ethane CH2 = CH2+H2O
CH3-CH2OH → CH2 = CH2+H2O (excess con H2SO4)
(note that "= "is the double bond)
heating thane at 443 k with excess con H2SO4 result in the dehydration of ethanol to give ethane
the reaction is: C₂H₆ + 2O₂ → 2CO₂ + 3H₂O So, this makes Z an ethane.
compound y will be alkane
z=CH3-CH3
C₂H₄ + H₂→C₂H₆(nickel catalyst (H2))
hope this will help you
y=ethane CH2 = CH2+H2O
CH3-CH2OH → CH2 = CH2+H2O (excess con H2SO4)
(note that "= "is the double bond)
heating thane at 443 k with excess con H2SO4 result in the dehydration of ethanol to give ethane
the reaction is: C₂H₆ + 2O₂ → 2CO₂ + 3H₂O So, this makes Z an ethane.
compound y will be alkane
z=CH3-CH3
C₂H₄ + H₂→C₂H₆(nickel catalyst (H2))
hope this will help you
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