solve the question no.19
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Let us 8√2 + 5√5 as ' a + b ' and 8√2 - 5√5 as ' a - b '
=> 3/a+b + 2/a-b
=3(a-b) + 2 (a+b) / (a+b)( a-b )
= 3a - 3b +2a+2b / a² - b²
=5a - b / a² - b² --------------------(1)
Substitute a = 8√2 and b as 5√5 in (1)
= 5(8√2) - 5(√5) / (8√2)² - (5√5)²
= 5 (8√2 - √5) / 128 - 125
= 5 (8√2 - √5) / 3
Hope it helps!!
Cheers!!
=> 3/a+b + 2/a-b
=3(a-b) + 2 (a+b) / (a+b)( a-b )
= 3a - 3b +2a+2b / a² - b²
=5a - b / a² - b² --------------------(1)
Substitute a = 8√2 and b as 5√5 in (1)
= 5(8√2) - 5(√5) / (8√2)² - (5√5)²
= 5 (8√2 - √5) / 128 - 125
= 5 (8√2 - √5) / 3
Hope it helps!!
Cheers!!
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Answer:
Kalpesh Prabhakar has given you the answer Buddy
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