Math, asked by reetabharti25638, 10 months ago

Solve the question no.23

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Answered by brainer9657
1

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PQ = PR

5y -7 = 3y-1

5y-3y=-1+7

2y = 6

y = 3

QR = 4y + 1= 4(3)+1=12+1 = 13

PQ = 5y-7=5(3)-7=15-7 = 8

PR = 3y-1=3(3)-1 = 9 -1 = 8

Perimeter = PQ + QR + PR = 13+8+8 = 29

Answered by saptarshihalder67
0

Answer:

y=  8 units and Perimeter = 29 units

Step-by-step explanation:

Given QP = PR,

hence,

5 y- 7=3 y- 1

2 y =6 units

hence y = 3 units

Now finding the length of 3 sides.

PQ = 5y-7

or, 5 x 3- 7 (placing the value of y in the equation)

= 8 units

Hence ,PQ= 8 units

as QP = PR (Given)

PR= 8. units

Given QR= 4 y+1

=4 x 3 +1 (placing the value of y in the equation)

=13 units

Hence QR=13 units

Perimeter=  P Q + Q R + P R

(Placing the values of 3 sides)

=13+8+8

= 29 units

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