Solve the question no.23
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Answered by
1
PQ = PR
5y -7 = 3y-1
5y-3y=-1+7
2y = 6
y = 3
QR = 4y + 1= 4(3)+1=12+1 = 13
PQ = 5y-7=5(3)-7=15-7 = 8
PR = 3y-1=3(3)-1 = 9 -1 = 8
Perimeter = PQ + QR + PR = 13+8+8 = 29
Answered by
0
Answer:
y= 8 units and Perimeter = 29 units
Step-by-step explanation:
Given QP = PR,
hence,
5 y- 7=3 y- 1
2 y =6 units
hence y = 3 units
Now finding the length of 3 sides.
PQ = 5y-7
or, 5 x 3- 7 (placing the value of y in the equation)
= 8 units
Hence ,PQ= 8 units
as QP = PR (Given)
PR= 8. units
Given QR= 4 y+1
=4 x 3 +1 (placing the value of y in the equation)
=13 units
Hence QR=13 units
Perimeter= P Q + Q R + P R
(Placing the values of 3 sides)
=13+8+8
= 29 units
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