solve the question no. 8 pls
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(a+b)^2=a^2+b^2+2ab
(8)^2=40+2ab
64-40=2ab
ab=12
a^3+b^3=(a+b)(a^2+b^2-ab)
=(8)(40-12)
=8×28
=224
is your answer
(8)^2=40+2ab
64-40=2ab
ab=12
a^3+b^3=(a+b)(a^2+b^2-ab)
=(8)(40-12)
=8×28
=224
is your answer
tarunyput:
how did you find out the value of -ab as -12?
please batao na
64-40=2ab,:24/2=ab',:ab=12
understand
ya or no
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0
the correct answer is 224
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