Solve the question no spaming else your id will be deleted! Give answer for both
Answers
Step-by-step explanation:
Solution :-
1)
Given equation :
(3/4)(7x-1)-[2x-(1-x)/2] = x+(3/2)
=> [(21x-3)/4]-[{4x-(1-x)}/2] = (2x+3)/2
=> [(21x-3)/4]-[(4x-1+x)/2] = (2x+3)/2
=> [(21x-3)/4]-[(5x-1)/2] = (2x+3)/2
LCM of 4 and 2 = 4
=> [(21x-3)-2(5x-1)]/4 = (2x+3)/2
=> (21x-3-10x+2)/4 = (2x+3)/2
=> (11x-1)/4 = (2x+3)/2
On applying cross multiplication then
=> 2(11x-1) = 4(2x+3)
=> 22x-2 = 8x+12
=> 22x-8x = 12+2
=> 14x = 14
=> x = 14/14
=> x = 1
Therefore, x = 1
2)
Given equation :
(-5x+2)/4 + (2x-4)/2 = (-5x-22)/4
LCM of 4 and 2 = 4
=> [(-5x+2)+2(2x-4)]/4 = (-5x-22)/4
=> (-5x+2+4x-8)/4 = (-5x-22)/4
=> (-x-6)/4 = (-5x-22)/4
On cancelling 4 both sides then
=> -x-6 = -5x-22
=>-x+5x = -22+6
=> 4x = -16
=> x = -16/4
=> x = -4
Therefore, x = -4
Answer :-
1) The value of x = 1
2) The value of x = -4
Answer:
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