Math, asked by sss64, 1 year ago

solve the question number 31

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Answered by pinakimandal53
1
ANSWER WITH FULL EXPLANATION

First, find the value of n in the first equation given. 
\sqrt{5^{n}}=125
⇒ (5^{n})^{\frac{1}{2}}=125    [∵ \sqrt{x} = x^{\frac{1}{2}}]
⇒ 5^{(n*\frac{1}{2})}=125    [∵ (x^{m})^{n}=x^{(m*n)}]
⇒ 5^{\frac{n}{2}}=125
⇒ 5^{\frac{n}{2}}=5^{3}   [∵ 125=5^{3}]
⇒ \frac{n}{2}=3    [If x^{m}=x^{n}, then m=n]
Multiplying both sides by 2. 
\frac{n}{2}*2=3*2
n=6

Now, we know that n=6. We have to substitute this value into the given expression 5^{\sqrt[n]{64}}
5^{\sqrt[n]{64}}
=5^{\sqrt[6]{64}}    [Substituting n=6. ]
=5^{2}    [∵ \sqrt[6]{64}=2]
=25

5^{\sqrt[n]{64}}=25

Hope this may help you. 

If you have any doubt, then you can ask me in the comments. 

sss64: thank you so much
pinakimandal53: You're welcome.
pinakimandal53: Please mark this answer as the brainliest, if it helps.
sss64: please tell me how to mark as the brainliest
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