Question

solve the question number c​

Answer 1

Answer:

by using identity (a+b)² = a²+b²+2ab , we get -

(3x²/4+4y²/7)²

= 9x⁴/16 + 16y⁴/49 + 6/7x²y²

Step-by-step explanation:

follow me and mark it as a brainliest answer

Answer 2

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\underline{\textbf{\textsf{\orange{Solution:}}}}$

$\: \: \bullet \small\green{ \bold{ \underline{step \: by \: step \: explaination}}}$

$\: \: \\ \quad \implies \displaystyle \sf{ \bigg( \frac{3 {x}^{2} }{7} + \frac{4 {y}^{2} }{7} \bigg) \bigg( \frac{ 3{x}^{2} }{4} + \frac{4 {y}^{2} }{7} } \bigg)$

$\: \: \\ \quad \implies \displaystyle \sf{ \bigg(\frac{ 3{x}^{2} }{7} } \bigg( \frac{ 3{x}^{2} }{4} + \frac{ 4{y}^{2} }{7} \bigg) + \frac{ 4{y}^{2} }{7} \bigg( \frac{ 3{x}^{2} }{4} + \frac{ 4{y}^{2} }{7} \bigg) \bigg)$

$\: \\ \quad \implies \displaystyle \sf{ \bigg( \frac{ 9{x}^{4} }{28} + \frac{ 12{x}^{2} {y}^{2} }{49} } + \frac{ 12{x}^{2} {y}^{2} }{28} + \frac{ 16{y}^{4} }{49} \bigg)$

$\\ \quad \implies \displaystyle \sf{ \bigg( \frac{9 {x}^{4} }{28} + \frac{12 {x}^{2} {y}^{2} }{49} + \frac{3 \times 7 {x}^{2} {y}^{2} }{49} + \frac{16 {y}^{4} }{49} } \bigg)$

$\: \: \\ \quad \implies \displaystyle \sf{ \bigg( \frac{ 9{x}^{4} }{28} + \frac{33 {x}^{2} {y}^{2} }{49} + \frac{ 16{y}^{4} }{49} \bigg)}$

$\: \: \\ \quad \implies \boxed{ \boxed{ \displaystyle \sf{ \bigg( \frac{9 {x}^{4} }{28} + \frac{32 {x}^{2} {y}^{2} }{49} + \frac{16 {y}^{4} }{49} \bigg) }} }$

$\pink{▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬}$