Question

solve the question please ​

Answer 1

Given, anglePQR=60°

angle SPR=55°

angle SPQ=c°

angle PSQ=a°

angle PSR=b°

angle PRQ=40°

In ∆PQR,

angle PQR+angle QPR+angle PRQ=180° (angle sum property)

60°+c°+55°+40°=180°

c°=180°-155°

c°=25°

In ∆PQS,

angle PQS+angle PSQ+angle QPS=180° (angle sum property)

60°+a°+c°=180°

60°+a°+25°=180°

a°=180°-85°

a°=95°

In ∆PSR,

angle SPR+angle PSR+angle PRS=180° (angle sum property)

55°+b°+40°=180°

b°=180°-95°

b°=85°

Therefore, Angle a°=95°

Angle b°=85°

Angle c°=25°