Question

solve the question please ​

Answer 1

Answer:

40√3+20 and 40

Step-by-step explanation:

Assuming X a point where the perpendicular of point A from the line AP meets line BC.

Triangle BAX will be right angled triangle.

Using trigonometry

cos 60 is equal to 1 by 2

cos is adjacent over hypotenuse

thus AX equals half of AB or 40km

Thus

ThusAX = PC = 40 km

now bx using sin 60 will be √3/2

Thus BX = 40√3

and BC which is base to point B is 40√3 plus 20

Adding 20 because of the extra AP height

therefore height of rocket at point B from ground 40√3 + 20 km

And PC equals 40 km

hope you mark it brainliest :)