Question

solve the question please with any one method of this : Elimination or cross multiplication
And if you don't know the answer please don't tell me if anybody konw then only tell this is not warning this appeal from me to those who see please tell me it's very important ​

Answer 1

Answer:

by solving the equations by lcm

9y+4x=-2xy

6y+4x=-xy

now try eliminating xy mltiply equation 2 with 2 and subtract

-3y-4x=0

y=4x/3

substitute in equation 1

12x+4x=-2xy

we cancel x saying that x is not equal to 0 then y=-8

similarly put y in equation 2 or 1

i put in 2

-48 +4x=8x

x=-12

so, x=-12,y=-8

 

i hope it helps

enjoy :)

Answer 2

Given:

3/2x + 2/3y = -1/3

3/4x + 1/2y = -1/8

Solution:

3/2x + 2/3y = -1/3 ______(1)

3/4x + 1/2y = -1/8 ______(2)

Multiply equation (1) by 1/2

1/2(3/2x + 2/3y = -1/3)

= 3/4x + 1/3y = -1/6 _____(3)

Subtract equation (2) from equation (3)

→ 3/4x + 1/2y - (3/4x + 1/3y) = -1/6 - (-1/8)

→ 3/4x - 1/2y - 3/4x - 1/3y = -1/6 + 1/8

→ (-3-2)/6y = (-4+3)/24

→ (-5)/6y = -1/2

→ y = (-1/2 × -6/5)

→ y = 3/5

Put y = 3/5 in equation (2)

→ 3/4x + (1/2 × 3/5) = -1/8

→ 3/4x + 3/10 = -1/8

→ 3/4x = -1/8 - 3/10

→ 3/4x = (-5-12)/40

→ 3/4x = -17/40

→ x = -17/40 × 4/3

→ x = -17/30

We get,

• x = -17/30
• y = 3/5