Question

solve the question plz......​

Answer 1

Answer:

$given \\ x + \frac{1}{x} = p \\ square \\ (x + \frac{1}{x} ) { }^{2} = {p}^{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2(x)( \frac{1}{x} ) = {p}^{2} \\ {x }^{2} + \frac{1}{ {x}^{2} } = {p}^{2} - 2 \\ let \\ y = x - \frac{1}{x} \\ square \\ {y}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2 \\ {y}^{2} = {p}^{2} - 2 - 2 \\ y = \sqrt{ {p}^{2} - 4}$