Solve the question plz
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THE THE PROPERTIES USED IN THIS QUESTION IS THAT TANGENT DRAWN TO A CIRCLE FROM THE SAME POINT ARE EQUAL.
AR=AQ(16 CM)
BQ=AB-AQ=14 CM
BP=PB=14 CM.
NOW SINCE BQ=BP, WE CAN SAFELY ASSUME THAT OPBQ IS A SQUARE.
THEREFORE,
OP=14 CM.(RADIUS OF CIRCLE)
AR=AQ(16 CM)
BQ=AB-AQ=14 CM
BP=PB=14 CM.
NOW SINCE BQ=BP, WE CAN SAFELY ASSUME THAT OPBQ IS A SQUARE.
THEREFORE,
OP=14 CM.(RADIUS OF CIRCLE)
Answered by
1
THE PROPERTIES USED IN THIS QUESTION IS THAT TANGENT DRAWN TO A CIRCLE FROM THE SAME POINT ARE EQUAL.
AR=AQ(16 CM)
BQ=AB-AQ=14 CM
BP=PB=14 CM.
NOW SINCE BQ=BP, WE CAN SAFELY ASSUME THAT OPBQ IS A SQUARE.
THEREFORE,
OP=14 CM.(RADIUS OF CIRCLE)
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