Math, asked by Anonymous, 1 year ago

Solve the question plz

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Answered by GeN21
1
THE THE PROPERTIES USED IN THIS QUESTION IS THAT TANGENT DRAWN TO A CIRCLE FROM THE SAME POINT ARE EQUAL.

AR=AQ(16 CM)
BQ=AB-AQ=14 CM
BP=PB=14 CM.

NOW SINCE BQ=BP, WE CAN SAFELY ASSUME THAT OPBQ IS A SQUARE.

THEREFORE,
OP=14 CM.(RADIUS OF CIRCLE)
Answered by ka52985
1

THE PROPERTIES USED IN THIS QUESTION IS THAT TANGENT DRAWN TO A CIRCLE FROM THE SAME POINT ARE EQUAL.


AR=AQ(16 CM)

BQ=AB-AQ=14 CM

BP=PB=14 CM.


NOW SINCE BQ=BP, WE CAN SAFELY ASSUME THAT OPBQ IS A SQUARE.


THEREFORE,

OP=14 CM.(RADIUS OF CIRCLE)


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