Math, asked by sandeep2597, 1 year ago

solve the question plz ​

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Answered by Abhishek474241
0
HEY FRIEND
HERE IS YR ANS..
_______



LET the side of first square be x
and second be y

A/Q

x {}^{2} + y {}^{2} = 468
thn
there perimeter difference is
4x-4y=24
x-y=6


=>(x-y)²=x²+y²-2xy
=>36=468-2xy
=>36-468=-2xy
=>-432=-2xy
xy=216
(X+Y)²=x²+y²+2xy
=468+432
=900
x+y=30


x+y=30
x-y=6
______
2x=36
x=18
y=12



HOPE IT HELP

sandeep2597: next
Abhishek474241: i completed it now u can see
sandeep2597: ok
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