Question

solve the question
plz
question 10

Answer 1

★ Hi , there !!★


here is your answer !!


x = - √2



p ( x ) => x² + √2x + k ------------------ eq ( 1 )






now ,


on , putting the value of x on equation 1 we get :-


( -√2 ) ² + ( √2 ) (-√ 2 ) + k = 0


=> 2 - 2 + k = 0



k = 0



hope it helps you dear !!


thanks !!!

Answer 2

hope it will help U......