Question

solve the question plzzzzz

Answer 1

Hlo friend... Cutiepie Here..

Nice question..

Here is ur answer :

(a) Sum of all the internal angles of a Quadrilateral is 360°

$x - 10 + x + 25 + x - 35 + x - 20 = 360$

$4x - 65 + 25 = 360$

$4x - 40 = 360$

$4x = 360 - 40$

$4x = 320$

$x = \frac{320}{4}$

$x = 80$



(b)
$x + 120 = 180 \: \: (linear \: equation)$

$x = 180 - 120$

$x = 60$

Sum of all the angles of a Quadrilateral.


$x + 2x + x + 20 + 60 = 360$


$4x + 80 = 360$


$4x = 360 - 80$


$4x = 280$


$x = \frac{280}{4}$


$x = 70$


(c) Sum of all the internal angles of a pentagon is 540.

$x + 9 + x + 7 + x + x + 12 + x + 22 = 540$


$5x + 50 = 540$


$5x = 540 - 50$


$5x = 490$


$x = \frac{490}{5}$

$x = 95$


ANS

(a) 80

(b) 70

(c) 95


HOPE IT HELPS YOU...

REGARDS
@sunita

Answer 2

hope this answer is correct