Question

solve the question? question is attached in image​

Answer 1

Explanation:

we know that

∆G=∆G°+RTln(Q)

where G is Gibbs free energy,G° is standard Gibbs free energy ,R is gas constant, T is temperature...

So at equilibrium,∆G =0

so ∆G°= -RTln(Kc)

[as at equilibrium Q=Kc]

.. substitute respective values of R,T and Kc and calculate answer.