Question

solve the question right now​

Answer 1

Answer:

13/4/{5/4-1/2(5/2-1/12)}(bcz lcm of 6 and r is 24)

lcm of 2 and 12 is 12

13/4/{5/4-1/2(29/12)}

13/4/{5/4-1/2.29/12}

13/4/{5/4-29/24}

13/4/{1/24}(bcz lcm of 4 and 24 is 24)

13/4.24(bcz when divide is changed to multiply,term us reciprocal)

hence,78 is the answer

hope it helped u

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Answer 2

Question :-

Solve this Equation -

$[3\frac{1}{4} \div \{1\frac{1}{4}-\frac{1}{2} (2\frac{1}{2} - \overline{\frac{1}{4} - \frac{1}{6}} )\}]$

Solution :-

We have to solve it using BODMAS,

B - Bracket  

O - Of  

D - Division  

M - Multiplication  

A - Addition  

S - Subtraction

It means we have to solve the given question using above listed steps.

First step is to solve the expression in bracket,  

Then, of [it is used to multiply two expressions] will be solved.  

After that Division, Multiplication, Addition and last Subtraction will be solved.  

Now, Solving it.

$=> [3\frac{1}{4} \div \{1\frac{1}{4}-\frac{1}{2} (2\frac{1}{2} - \overline{\frac{1}{4} - \frac{1}{6}} )\}]\\ \\ => [\frac{13}{4} \div \{\frac{5}{4}-\frac{1}{2} (\frac{5}{2} - \overline{\frac{1}{4} - \frac{1}{6}} )\}] \\ \\ => [\frac{13}{4} \div \{\frac{5}{4}-\frac{1}{2} (\frac{5}{2} - \overline{\frac{6-4}{12}} )\}]\\\\=>[\frac{13}{4} \div \{\frac{5}{4}-\frac{1}{2} (\frac{5}{2} - {\frac{2}{12}} )\}]$

$=>[\frac{13}{4} \div \{\frac{5}{4}-\frac{1}{2} ({\frac{5 \times 6-30}{12}} )\}]\\\\=>[\frac{13}{4} \div \{\frac{5}{4}-\frac{1}{2} ({\frac{30-30}{12}} )\}]\\\\=>[\frac{13}{4} \div \{\frac{5}{4}-\frac{1}{2} \times (\frac{0}{12} )\}]\\\\=>[\frac{13}{4} \div \{\frac{5}{4}-\frac{1}{2} \times (0)\}]\\\\=>[\frac{13}{4} \div \{\frac{5}{4}-0\}]\\\\=>[\frac{13}{4} \div \{\frac{5}{4}\}]\\\\=>[\frac{13}{4} \times \frac{4}{5}]\\\\=> \frac{13}{5}$

Answer :-

The answer after solving the question is -

=> $\frac{13}{5}$