Question

solve the question seen in the attachment ​

Answer 1

Step-by-step explanation:

given,

AD=DC

AB=BC

To Prove,

BD bisects angle B and D as well

angle ABD=CBD

Angle ADB=BDC

Proof,

In triangle ABD and CBD

AD=DC{given}

AB=BC{given}

BD=DB[common}

By SSS congruency rule Triangle ABD is congruent to CBD

ii) As triangle ABD is congruent to triangle CBD

So by CPCT Angle ABD=CBD

And again by CPCT ADB=BDC

therefore BD bisects angle D and Angle B as well

hence proved

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Answer 2

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