Question

solve the question seen in the attachment ​

Answer 1

Answer:

Statements:

AM=AM(common)

BM=MC (M is the mid point of BC divides)

AB=AC (given)

Triangle ABM is congruent to triangle ACM (by SSS rule of congurency)

angle CAM=angle BAM(cpct)

angle CAM=25°

angle ABM=angle ACM(cpct)

angle ABM=65°

Now,In triangle AMC

angle M=90°(AM perpendicular to BC)

angle A+angle M+angle C=180(Sum of angles of a triangle=180°)

25°+angle M+65=180

angle M+90=180

angle M=180-90

angle M=90°

Angle AMC=90° Answer.

Answer 2

Answer:

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