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Explanation:
Join AP
In triangle ABP and ACP;
AB=AC (given)
PB=PC (given)
AP=AP (common)
By S-S-S congruence criteria
Triangle ABP is congruent to triangle ACP
Answered by
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Explanation:
given,
AB=AC
PB=PC
To prove: ∆ABP ≈ ∆APC
cons: join AP
proof: In ∆APB and ∆APC
AB=AC (given)
PB=PC (given)
AP=AP (common)
hence ∆ABP ≈ ∆APC by SAS congurency
....666.....
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